Chemguide: Support for CIE A level Chemistry

Learning outcome 17.1(c)

This statement is about using the triiodomethane (iodoform) reaction to identify the CH3CH(OH)- group in alcohols

Before you go on, you should find and read the statement in your copy of the syllabus.

You will find what you need on the page about the triiodomethane (iodoform) reaction with alcohols

For CIE purposes, you only need to learn the method using iodine and sodium hydroxide solution.

The most important section on this page is under the heading "What the triiodomethane (iodoform) reaction shows".

The full equation for the reaction isn't given on that page. For a general alcohol which undergoes the reaction, and where R is any hydrocarbon group or a hydrogen atom, the equation is:

At the time of writing, this equation had never been asked in an exam. CIE teacher support material does, however, say that it should be taught.

My advice would be that this is such a bother to learn that you would probably be safe to ignore it until you have learnt everything else on the syllabus.

You will, however, be expected to be able to write the structures of both of the organic products of the reaction - the triiodomethane and the sodium salt, RCOONa. You could equally well give this in the form of the carboxylate ion, as shown at the bottom of the page you will have read.

Note:  A carboxylate ion is the negative ion from a carboxylic acid such as ethanoic acid, CH3COOH. A general carboxylic acid is written as RCOOH.

So, sodium ethanoate has the formula CH3COONa, and contains the ethanoate ion, CH3COO-.

Go to the Section 17 Menu . . .

To return to the list of learning outcomes in Section 17

Go to the CIE Main Menu . . .

To return to the list of all the CIE sections

Go to Chemguide Main Menu . . .

This will take you to the main part of Chemguide.

© Jim Clark 2010 (last modified June 2014)