Chemguide: Support for CIE A level Chemistry

Learning outcome 6.3(f)

This statement is about how their E° values relate to the reactivity of the halogens as oxidising agents.

Before you go on, you should find and read the statement in your copy of the syllabus.

The E° values

You will remember that the oxidising ability of the halogens decreases as you go down the Group in the Periodic Table.

The E° values of the four halogens from fluorine to iodine are:

Remember that the electrode potentials give a measure of the positions of the equilibria. The more positive, the further the equilibrium lies to the right.

In the fluorine case, the E° value is almost as positive as they get. That means that fluorine will very readily pick up electrons to make fluoride ions.

Fluorine will therefore remove electrons from other things extremely well. Taking electrons away from something is oxidising it. So fluorine is a very powerful oxidising agent indeed.

As you go down the rest of the group, the E° values become less positive, and so the oxidising ability decreases.

Three simple examples of this

Why does chlorine oxidise iodide ions to iodine?

The two E° values are:

When you couple two of these equilibria together in a test tube, the more positive one will tend to move to the right, and the more negative one (or less positive one) to the left.

That is exactly what you want to happen to turn iodide ions into iodine. The chlorine E° is more positive, and so chlorine molecules take electrons from the iodide ions to turn them into iodine.

Why won't bromine oxidise chloride ions to chlorine?

The two E° values are:

The chlorine equilibrium lies further to the right because it is the more positive. That means that if you couple the two equilibria together, you would expect the chlorine one to move to the right and the bromine one to the left.

But if you start with bromine and chloride ions, the two equilibria are already as far in those directions as possible. To get a reaction, they would have to move in a direction opposite to that predicted by the E° values. That can't happen.

Which halogens could you use to oxidise Fe2+ to Fe3+?

The E° value for the iron(II) / iron(III) system is

. . . and what you want to do is to drive it to the left to turn Fe2+ into Fe3+. To do that you would need to couple it with something with a more positive E° value.

If you look at the halogen list above, you will see that fluorine, chlorine and bromine are all capable of oxidising iron(II) to iron(III), but iodine isn't.

Go to the Section 6 Menu . . .

To return to the list of learning outcomes in Section 6

Go to the CIE Main Menu . . .

To return to the list of all the CIE sections

Go to Chemguide Main Menu . . .

This will take you to the main part of Chemguide.

© Jim Clark 2011 (last modified April 2016)